6b-2(b+3)=2(b-5)

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Solution for 6b-2(b+3)=2(b-5) equation: 



6b-2(b+3)=2(b-5)

We move all terms to the left:

6b-2(b+3)-(2(b-5))=0

We multiply parentheses

6b-2b-(2(b-5))-6=0



We calculate terms in parentheses: -(2(b-5)), so:

2(b-5)

We multiply parentheses

2b-10

Back to the equation:

-(2b-10)



We add all the numbers together, and all the variables

4b-(2b-10)-6=0

We get rid of parentheses

4b-2b+10-6=0

We add all the numbers together, and all the variables

2b+4=0

We move all terms containing b to the left, all other terms to the right

2b=-4

b=-4/2

b=-2

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