3(2x+3-4)(x-1)=3

Solution for 3(2x+3-4)(x-1)=3 equation:

3(2x+3-4)(x-1)=3

We move all terms to the left:

3(2x+3-4)(x-1)-(3)=0

We add all the numbers together, and all the variables

3(2x-1)(x-1)-3=0

We multiply parentheses ..

3(+2x^2-2x-1x+1)-3=0

We multiply parentheses

6x^2-6x-3x+3-3=0

We add all the numbers together, and all the variables

6x^2-9x=0

a = 6; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·6·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*6}=\frac{18}{12}
=1+1/2
$