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3(2x+3)=-5(3x-3)-2x
We move all terms to the left:
3(2x+3)-(-5(3x-3)-2x)=0
We multiply parentheses
6x-(-5(3x-3)-2x)+9=0
We calculate terms in parentheses: -(-5(3x-3)-2x), so:We get rid of parentheses
-5(3x-3)-2x
We add all the numbers together, and all the variables
-2x-5(3x-3)
We multiply parentheses
-2x-15x+15
We add all the numbers together, and all the variables
-17x+15
Back to the equation:
-(-17x+15)
6x+17x-15+9=0
We add all the numbers together, and all the variables
23x-6=0
We move all terms containing x to the left, all other terms to the right
23x=6
x=6/23
x=6/23
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