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3(2x+3)=-(3x-3)-2x
We move all terms to the left:
3(2x+3)-(-(3x-3)-2x)=0
We multiply parentheses
6x-(-(3x-3)-2x)+9=0
We calculate terms in parentheses: -(-(3x-3)-2x), so:We get rid of parentheses
-(3x-3)-2x
We add all the numbers together, and all the variables
-2x-(3x-3)
We get rid of parentheses
-2x-3x+3
We add all the numbers together, and all the variables
-5x+3
Back to the equation:
-(-5x+3)
6x+5x-3+9=0
We add all the numbers together, and all the variables
11x+6=0
We move all terms containing x to the left, all other terms to the right
11x=-6
x=-6/11
x=-6/11
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