3(2x+3)+11=-2(2x-6)-18

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Solution for 3(2x+3)+11=-2(2x-6)-18 equation: 



3(2x+3)+11=-2(2x-6)-18

We move all terms to the left:

3(2x+3)+11-(-2(2x-6)-18)=0

We multiply parentheses

6x-(-2(2x-6)-18)+9+11=0



We calculate terms in parentheses: -(-2(2x-6)-18), so:

-2(2x-6)-18

We multiply parentheses

-4x+12-18

We add all the numbers together, and all the variables

-4x-6

Back to the equation:

-(-4x-6)



We add all the numbers together, and all the variables

6x-(-4x-6)+20=0

We get rid of parentheses

6x+4x+6+20=0

We add all the numbers together, and all the variables

10x+26=0

We move all terms containing x to the left, all other terms to the right

10x=-26

x=-26/10

x=-2+3/5

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