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12=1/2(12m+8)+2m
We move all terms to the left:
12-(1/2(12m+8)+2m)=0
Domain of the equation: 2(12m+8)+2m)!=0We multiply all the terms by the denominator
m∈R
-(1+12*2(12m+8)+2m)=0
We calculate terms in parentheses: -(1+12*2(12m+8)+2m), so:We add all the numbers together, and all the variables
1+12*2(12m+8)+2m
determiningTheFunctionDomain 12*2(12m+8)+2m+1
We add all the numbers together, and all the variables
2m+12*2(12m+8)+1
Wy multiply elements
2m+24m(1+1
Back to the equation:
-(2m+24m(1+1)
-(2m+24m2=0
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