3(2x+2)=3x+1-(6x-0)

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Solution for 3(2x+2)=3x+1-(6x-0) equation: 



3(2x+2)=3x+1-(6x-0)

We move all terms to the left:

3(2x+2)-(3x+1-(6x-0))=0

We add all the numbers together, and all the variables

3(2x+2)-(3x+1-(+6x))=0

We multiply parentheses

6x-(3x+1-(+6x))+6=0



We calculate terms in parentheses: -(3x+1-(+6x)), so:

3x+1-(+6x)

determiningTheFunctionDomain
3x-(+6x)+1

We get rid of parentheses

3x-6x+1

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We get rid of parentheses

6x+3x-1+6=0

We add all the numbers together, and all the variables

9x+5=0

We move all terms containing x to the left, all other terms to the right

9x=-5

x=-5/9

x=-5/9

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