3=(1/6)(10x-18)

Solution for 3=(1/6)(10x-18) equation:

3=(1/6)(10x-18)

We move all terms to the left:

3-((1/6)(10x-18))=0


Domain of the equation: 6)(10x-18))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/6)(10x-18))+3=0

We multiply parentheses ..

-((+10x^2+1/6*-18))+3=0

We multiply all the terms by the denominator


-((+10x^2+1+3*6*-18))=0


We calculate terms in parentheses: -((+10x^2+1+3*6*-18)), so:

(+10x^2+1+3*6*-18)

We get rid of parentheses

10x^2+1-18+3*6*

We add all the numbers together, and all the variables

10x^2

Back to the equation:

-(10x^2)


a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$