3(2x+2)=2(x+4)+x+22

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Solution for 3(2x+2)=2(x+4)+x+22 equation: 



3(2x+2)=2(x+4)+x+22

We move all terms to the left:

3(2x+2)-(2(x+4)+x+22)=0

We multiply parentheses

6x-(2(x+4)+x+22)+6=0



We calculate terms in parentheses: -(2(x+4)+x+22), so:

2(x+4)+x+22

We add all the numbers together, and all the variables

x+2(x+4)+22

We multiply parentheses

x+2x+8+22

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)



We get rid of parentheses

6x-3x-30+6=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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