5(2x+1)=2x+3(4+x)+15

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Solution for 5(2x+1)=2x+3(4+x)+15 equation: 



5(2x+1)=2x+3(4+x)+15

We move all terms to the left:

5(2x+1)-(2x+3(4+x)+15)=0

We add all the numbers together, and all the variables

5(2x+1)-(2x+3(x+4)+15)=0

We multiply parentheses

10x-(2x+3(x+4)+15)+5=0



We calculate terms in parentheses: -(2x+3(x+4)+15), so:

2x+3(x+4)+15

We multiply parentheses

2x+3x+12+15

We add all the numbers together, and all the variables

5x+27

Back to the equation:

-(5x+27)



We get rid of parentheses

10x-5x-27+5=0

We add all the numbers together, and all the variables

5x-22=0

We move all terms containing x to the left, all other terms to the right

5x=22

x=22/5

x=4+2/5

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