3(2x+12)=-(x-4)+x

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Solution for 3(2x+12)=-(x-4)+x equation: 



3(2x+12)=-(x-4)+x

We move all terms to the left:

3(2x+12)-(-(x-4)+x)=0

We multiply parentheses

6x-(-(x-4)+x)+36=0



We calculate terms in parentheses: -(-(x-4)+x), so:

-(x-4)+x

We add all the numbers together, and all the variables

x-(x-4)

We get rid of parentheses

x-x+4

We add all the numbers together, and all the variables

4

Back to the equation:

-(4)



We add all the numbers together, and all the variables

6x+32=0

We move all terms containing x to the left, all other terms to the right

6x=-32

x=-32/6

x=-5+1/3

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