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49x^2=7
We move all terms to the left:
49x^2-(7)=0
a = 49; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·49·(-7)
Δ = 1372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1372}=\sqrt{196*7}=\sqrt{196}*\sqrt{7}=14\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{7}}{2*49}=\frac{0-14\sqrt{7}}{98} =-\frac{14\sqrt{7}}{98} =-\frac{\sqrt{7}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{7}}{2*49}=\frac{0+14\sqrt{7}}{98} =\frac{14\sqrt{7}}{98} =\frac{\sqrt{7}}{7} $
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