3(2x+1)=8(2x+9)

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Solution for 3(2x+1)=8(2x+9) equation: 



3(2x+1)=8(2x+9)

We move all terms to the left:

3(2x+1)-(8(2x+9))=0

We multiply parentheses

6x-(8(2x+9))+3=0



We calculate terms in parentheses: -(8(2x+9)), so:

8(2x+9)

We multiply parentheses

16x+72

Back to the equation:

-(16x+72)



We get rid of parentheses

6x-16x-72+3=0

We add all the numbers together, and all the variables

-10x-69=0

We move all terms containing x to the left, all other terms to the right

-10x=69

x=69/-10

x=-6+9/10

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