-3=2(z+-3)-11

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Solution for -3=2(z+-3)-11 equation: 



-3=2(z+-3)-11

We move all terms to the left:

-3-(2(z+-3)-11)=0

We add all the numbers together, and all the variables

-(2(z-3)-11)-3=0



We calculate terms in parentheses: -(2(z-3)-11), so:

2(z-3)-11

We multiply parentheses

2z-6-11

We add all the numbers together, and all the variables

2z-17

Back to the equation:

-(2z-17)



We get rid of parentheses

-2z+17-3=0

We add all the numbers together, and all the variables

-2z+14=0

We move all terms containing z to the left, all other terms to the right

-2z=-14

z=-14/-2

z=+7

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