3(2x+1)=5(x-4)=

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Solution for 3(2x+1)=5(x-4)= equation: 



3(2x+1)=5(x-4)=

We move all terms to the left:

3(2x+1)-(5(x-4))=0

We multiply parentheses

6x-(5(x-4))+3=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

6x-5x+20+3=0

We add all the numbers together, and all the variables

x+23=0

We move all terms containing x to the left, all other terms to the right

x=-23

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