-5(b+2)-7(b-5)=-11

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Solution for -5(b+2)-7(b-5)=-11 equation: 



-5(b+2)-7(b-5)=-11

We move all terms to the left:

-5(b+2)-7(b-5)-(-11)=0

We add all the numbers together, and all the variables

-5(b+2)-7(b-5)+11=0

We multiply parentheses

-5b-7b-10+35+11=0

We add all the numbers together, and all the variables

-12b+36=0

We move all terms containing b to the left, all other terms to the right

-12b=-36

b=-36/-12

b=+3

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