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3(2x+1)=2(3x+)+1
We move all terms to the left:
3(2x+1)-(2(3x+)+1)=0
We add all the numbers together, and all the variables
3(2x+1)-(2(+3x)+1)=0
We multiply parentheses
6x-(2(+3x)+1)+3=0
We calculate terms in parentheses: -(2(+3x)+1), so:We get rid of parentheses
2(+3x)+1
We multiply parentheses
6x+1
Back to the equation:
-(6x+1)
6x-6x-1+3=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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