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-3+3(5x+2)=2(x+1)+1
We move all terms to the left:
-3+3(5x+2)-(2(x+1)+1)=0
We multiply parentheses
15x-(2(x+1)+1)+6-3=0
We calculate terms in parentheses: -(2(x+1)+1), so:We add all the numbers together, and all the variables
2(x+1)+1
We multiply parentheses
2x+2+1
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
15x-(2x+3)+3=0
We get rid of parentheses
15x-2x-3+3=0
We add all the numbers together, and all the variables
13x=0
x=0/13
x=0
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