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3(2x+1)=2(1-5x)+6x+11
We move all terms to the left:
3(2x+1)-(2(1-5x)+6x+11)=0
We add all the numbers together, and all the variables
3(2x+1)-(2(-5x+1)+6x+11)=0
We multiply parentheses
6x-(2(-5x+1)+6x+11)+3=0
We calculate terms in parentheses: -(2(-5x+1)+6x+11), so:We get rid of parentheses
2(-5x+1)+6x+11
We add all the numbers together, and all the variables
6x+2(-5x+1)+11
We multiply parentheses
6x-10x+2+11
We add all the numbers together, and all the variables
-4x+13
Back to the equation:
-(-4x+13)
6x+4x-13+3=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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