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8/3x+5/6x=14
We move all terms to the left:
8/3x+5/6x-(14)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
48x/18x^2+15x/18x^2-14=0
We multiply all the terms by the denominator
48x+15x-14*18x^2=0
We add all the numbers together, and all the variables
63x-14*18x^2=0
Wy multiply elements
-252x^2+63x=0
a = -252; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-252)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-252}=\frac{-126}{-504} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-252}=\frac{0}{-504} =0 $
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