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3(2x+1)/5=(2x-5)
We move all terms to the left:
3(2x+1)/5-((2x-5))=0
We multiply all the terms by the denominator
3(2x+1)-(((2x-5)))*5=0
We multiply parentheses
6x-(((2x-5)))*5+3=0
We move all terms containing x to the left, all other terms to the right
6x-(((2x-5)))*5=-3
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