2t=4(t-1)+5

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Solution for 2t=4(t-1)+5 equation: 



2t=4(t-1)+5

We move all terms to the left:

2t-(4(t-1)+5)=0



We calculate terms in parentheses: -(4(t-1)+5), so:

4(t-1)+5

We multiply parentheses

4t-4+5

We add all the numbers together, and all the variables

4t+1

Back to the equation:

-(4t+1)



We get rid of parentheses

2t-4t-1=0

We add all the numbers together, and all the variables

-2t-1=0

We move all terms containing t to the left, all other terms to the right

-2t=1

t=1/-2

t=-1/2

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