3(2x+1)/2(x-5)-5(5-2x)=16

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Solution for 3(2x+1)/2(x-5)-5(5-2x)=16 equation: 



3(2x+1)/2(x-5)-5(5-2x)=16

We move all terms to the left:

3(2x+1)/2(x-5)-5(5-2x)-(16)=0



Domain of the equation: 2(x-5)!=0

x∈R



We add all the numbers together, and all the variables

3(2x+1)/2(x-5)-5(-2x+5)-16=0

We multiply parentheses

3(2x+1)/2(x-5)+10x-25-16=0

We multiply all the terms by the denominator


3(2x+1)+10x*2(x-5)-25*2(x-5)-16*2(x-5)=0

We multiply parentheses

6x+10x*2(x-5)-25*2(x-5)-16*2(x-5)+3=0

Wy multiply elements

20x^2(x-50x(x-32x(x+3+6x=0

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