(2x-1)/3=2-(x-5)/2

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Solution for (2x-1)/3=2-(x-5)/2 equation: 



(2x-1)/3=2-(x-5)/2

We move all terms to the left:

(2x-1)/3-(2-(x-5)/2)=0

We calculate fractions


2x/()+(-(2-(x-5)*3)/()=0



We calculate terms in parentheses: +(-(2-(x-5)*3)/(), so:

-(2-(x-5)*3)/(

We multiply all the terms by the denominator


-(2-(x-5)*3)



We calculate terms in parentheses: -(2-(x-5)*3), so:

2-(x-5)*3

determiningTheFunctionDomain
-(x-5)*3+2

We multiply parentheses

-3x+15+2

We add all the numbers together, and all the variables

-3x+17

Back to the equation:

-(-3x+17)



We get rid of parentheses

3x-17

Back to the equation:

+(3x-17)



We get rid of parentheses

2x/()+3x-17=0

We multiply all the terms by the denominator


2x+3x*()-17*()=0

We add all the numbers together, and all the variables

2x+3x*()=0

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