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3(2x+1)-2x=3(x+3)
We move all terms to the left:
3(2x+1)-2x-(3(x+3))=0
We add all the numbers together, and all the variables
-2x+3(2x+1)-(3(x+3))=0
We multiply parentheses
-2x+6x-(3(x+3))+3=0
We calculate terms in parentheses: -(3(x+3)), so:We add all the numbers together, and all the variables
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
4x-(3x+9)+3=0
We get rid of parentheses
4x-3x-9+3=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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