15=3(2c-3)

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Solution for 15=3(2c-3) equation: 



15=3(2c-3)

We move all terms to the left:

15-(3(2c-3))=0



We calculate terms in parentheses: -(3(2c-3)), so:

3(2c-3)

We multiply parentheses

6c-9

Back to the equation:

-(6c-9)



We get rid of parentheses

-6c+9+15=0

We add all the numbers together, and all the variables

-6c+24=0

We move all terms containing c to the left, all other terms to the right

-6c=-24

c=-24/-6

c=+4

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