3(2x+1)+7(6x-1)=23+(12x-7)

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Solution for 3(2x+1)+7(6x-1)=23+(12x-7) equation: 



3(2x+1)+7(6x-1)=23+(12x-7)

We move all terms to the left:

3(2x+1)+7(6x-1)-(23+(12x-7))=0

We multiply parentheses

6x+42x-(23+(12x-7))+3-7=0



We calculate terms in parentheses: -(23+(12x-7)), so:

23+(12x-7)

determiningTheFunctionDomain
(12x-7)+23

We get rid of parentheses

12x-7+23

We add all the numbers together, and all the variables

12x+16

Back to the equation:

-(12x+16)



We add all the numbers together, and all the variables

48x-(12x+16)-4=0

We get rid of parentheses

48x-12x-16-4=0

We add all the numbers together, and all the variables

36x-20=0

We move all terms containing x to the left, all other terms to the right

36x=20

x=20/36

x=5/9

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