x*2x+50x=650

Solution for x*2x+50x=650 equation:

x*2x+50x=650

We move all terms to the left:

x*2x+50x-(650)=0

We add all the numbers together, and all the variables

50x+x*2x-650=0

Wy multiply elements

2x^2+50x-650=0

a = 2; b = 50; c = -650;
Δ = b2-4ac
Δ = 502-4·2·(-650)
Δ = 7700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7700}=\sqrt{100*77}=\sqrt{100}*\sqrt{77}=10\sqrt{77}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{77}}{2*2}=\frac{-50-10\sqrt{77}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{77}}{2*2}=\frac{-50+10\sqrt{77}}{4}
$