3(2x+1)+56=10

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Solution for 3(2x+1)+56=10 equation: 



3(2x+1)+56=10

We move all terms to the left:

3(2x+1)+56-(10)=0

We add all the numbers together, and all the variables

3(2x+1)+46=0

We multiply parentheses

6x+3+46=0

We add all the numbers together, and all the variables

6x+49=0

We move all terms containing x to the left, all other terms to the right

6x=-49

x=-49/6

x=-8+1/6

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