3(2u-4)+6u=36

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Solution for 3(2u-4)+6u=36 equation: 



3(2u-4)+6u=36

We move all terms to the left:

3(2u-4)+6u-(36)=0

We add all the numbers together, and all the variables

6u+3(2u-4)-36=0

We multiply parentheses

6u+6u-12-36=0

We add all the numbers together, and all the variables

12u-48=0

We move all terms containing u to the left, all other terms to the right

12u=48

u=48/12

u=4

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