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6+6(2x-1)=3(1+4x)
We move all terms to the left:
6+6(2x-1)-(3(1+4x))=0
We add all the numbers together, and all the variables
6(2x-1)-(3(4x+1))+6=0
We multiply parentheses
12x-(3(4x+1))-6+6=0
We calculate terms in parentheses: -(3(4x+1)), so:We add all the numbers together, and all the variables
3(4x+1)
We multiply parentheses
12x+3
Back to the equation:
-(12x+3)
12x-(12x+3)=0
We get rid of parentheses
12x-12x-3=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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