3(2u-3)-2(u+4)=(u+8)

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Solution for 3(2u-3)-2(u+4)=(u+8) equation: 



3(2u-3)-2(u+4)=(u+8)

We move all terms to the left:

3(2u-3)-2(u+4)-((u+8))=0

We multiply parentheses

6u-2u-((u+8))-9-8=0



We calculate terms in parentheses: -((u+8)), so:

(u+8)

We get rid of parentheses

u+8

Back to the equation:

-(u+8)



We add all the numbers together, and all the variables

4u-(u+8)-17=0

We get rid of parentheses

4u-u-8-17=0

We add all the numbers together, and all the variables

3u-25=0

We move all terms containing u to the left, all other terms to the right

3u=25

u=25/3

u=8+1/3

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