2x+3=3(2x+3)-4x2x+3=3(2x+3)-4x

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Solution for 2x+3=3(2x+3)-4x2x+3=3(2x+3)-4x equation: 



2x+3=3(2x+3)-4x^2x+3=3(2x+3)-4x

We move all terms to the left:

2x+3-(3(2x+3)-4x^2x+3)=0



We calculate terms in parentheses: -(3(2x+3)-4x^2x+3), so:

3(2x+3)-4x^2x+3

determiningTheFunctionDomain
-4x^2x+3(2x+3)+3

We multiply parentheses

-4x^2x+6x+9+3

We add all the numbers together, and all the variables

-4x^2x+6x+12

Back to the equation:

-(-4x^2x+6x+12)



We get rid of parentheses

4x^2x-6x+2x-12+3=0

We add all the numbers together, and all the variables

4x^2x-4x-9=0

We move all terms containing x to the left, all other terms to the right

4x^2x-4x=9

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