3(2s+1)=3(4s-1)

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Solution for 3(2s+1)=3(4s-1) equation: 



3(2s+1)=3(4s-1)

We move all terms to the left:

3(2s+1)-(3(4s-1))=0

We multiply parentheses

6s-(3(4s-1))+3=0



We calculate terms in parentheses: -(3(4s-1)), so:

3(4s-1)

We multiply parentheses

12s-3

Back to the equation:

-(12s-3)



We get rid of parentheses

6s-12s+3+3=0

We add all the numbers together, and all the variables

-6s+6=0

We move all terms containing s to the left, all other terms to the right

-6s=-6

s=-6/-6

s=1

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