6(-k-3)=12

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Solution for 6(-k-3)=12 equation: 



6(-k-3)=12

We move all terms to the left:

6(-k-3)-(12)=0

We add all the numbers together, and all the variables

6(-1k-3)-12=0

We multiply parentheses

-6k-18-12=0

We add all the numbers together, and all the variables

-6k-30=0

We move all terms containing k to the left, all other terms to the right

-6k=30

k=30/-6

k=-5

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