3(2r+7)=15(r-4)

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Solution for 3(2r+7)=15(r-4) equation: 



3(2r+7)=15(r-4)

We move all terms to the left:

3(2r+7)-(15(r-4))=0

We multiply parentheses

6r-(15(r-4))+21=0



We calculate terms in parentheses: -(15(r-4)), so:

15(r-4)

We multiply parentheses

15r-60

Back to the equation:

-(15r-60)



We get rid of parentheses

6r-15r+60+21=0

We add all the numbers together, and all the variables

-9r+81=0

We move all terms containing r to the left, all other terms to the right

-9r=-81

r=-81/-9

r=+9

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