6(13-5x)+15x=14(4x-12)-8

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Solution for 6(13-5x)+15x=14(4x-12)-8 equation: 



6(13-5x)+15x=14(4x-12)-8

We move all terms to the left:

6(13-5x)+15x-(14(4x-12)-8)=0

We add all the numbers together, and all the variables

6(-5x+13)+15x-(14(4x-12)-8)=0

We add all the numbers together, and all the variables

15x+6(-5x+13)-(14(4x-12)-8)=0

We multiply parentheses

15x-30x-(14(4x-12)-8)+78=0



We calculate terms in parentheses: -(14(4x-12)-8), so:

14(4x-12)-8

We multiply parentheses

56x-168-8

We add all the numbers together, and all the variables

56x-176

Back to the equation:

-(56x-176)



We add all the numbers together, and all the variables

-15x-(56x-176)+78=0

We get rid of parentheses

-15x-56x+176+78=0

We add all the numbers together, and all the variables

-71x+254=0

We move all terms containing x to the left, all other terms to the right

-71x=-254

x=-254/-71

x=3+41/71

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