3(2p-10)+8=1/2(8p-16)+10

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Solution for 3(2p-10)+8=1/2(8p-16)+10 equation: 



3(2p-10)+8=1/2(8p-16)+10

We move all terms to the left:

3(2p-10)+8-(1/2(8p-16)+10)=0



Domain of the equation: 2(8p-16)+10)!=0

p∈R



We multiply parentheses

6p-(1/2(8p-16)+10)-30+8=0

We multiply all the terms by the denominator


6p*2(8p-16)-30*2(8p-16)+10)+8*2(8p+10)-(1-16)+10)=0

We add all the numbers together, and all the variables

6p*2(8p-16)-30*2(8p-16)+10)+8*2(8p+10)-(-15)+10)=0

We add all the numbers together, and all the variables

6p*2(8p-16)-30*2(8p-16)+10)+8*2(8p=0

Wy multiply elements

12p^2(8-60p(8+10)+8*2(8p=0

We add all the numbers together, and all the variables

12p^2(8-60p18+8*2(8p=0

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