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36a^2=-3a
We move all terms to the left:
36a^2-(-3a)=0
We get rid of parentheses
36a^2+3a=0
a = 36; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·36·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*36}=\frac{-6}{72} =-1/12 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*36}=\frac{0}{72} =0 $
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