3(2n-4)=3n+15

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Solution for 3(2n-4)=3n+15 equation: 



3(2n-4)=3n+15

We move all terms to the left:

3(2n-4)-(3n+15)=0

We multiply parentheses

6n-(3n+15)-12=0

We get rid of parentheses

6n-3n-15-12=0

We add all the numbers together, and all the variables

3n-27=0

We move all terms containing n to the left, all other terms to the right

3n=27

n=27/3

n=9

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