3(2n-4)-1/4=3/4(n+4)

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Solution for 3(2n-4)-1/4=3/4(n+4) equation: 



3(2n-4)-1/4=3/4(n+4)

We move all terms to the left:

3(2n-4)-1/4-(3/4(n+4))=0



Domain of the equation: 4(n+4))!=0

n∈R



We multiply parentheses

6n-(3/4(n+4))-12-1/4=0

We calculate fractions


6n-12=0

We move all terms containing n to the left, all other terms to the right

6n=12

n=12/6

n=2

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