40+x=70x2

Solution for 40+x=70x2 equation:

40+x=70x^2

We move all terms to the left:

40+x-(70x^2)=0

determiningTheFunctionDomain
-70x^2+x+40=0

a = -70; b = 1; c = +40;
Δ = b2-4ac
Δ = 12-4·(-70)·40
Δ = 11201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{11201}}{2*-70}=\frac{-1-\sqrt{11201}}{-140}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{11201}}{2*-70}=\frac{-1+\sqrt{11201}}{-140}
$