3(2n+2)=6(n+1)

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Solution for 3(2n+2)=6(n+1) equation: 



3(2n+2)=6(n+1)

We move all terms to the left:

3(2n+2)-(6(n+1))=0

We multiply parentheses

6n-(6(n+1))+6=0



We calculate terms in parentheses: -(6(n+1)), so:

6(n+1)

We multiply parentheses

6n+6

Back to the equation:

-(6n+6)



We get rid of parentheses

6n-6n-6+6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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