3/4g-3/5g-7/10=2

Solution for 3/4g-3/5g-7/10=2 equation:

3/4g-3/5g-7/10=2

We move all terms to the left:

3/4g-3/5g-7/10-(2)=0


Domain of the equation: 4g!=0

g!=0/4

g!=0

g∈R



Domain of the equation: 5g!=0

g!=0/5

g!=0

g∈R


determiningTheFunctionDomain
3/4g-3/5g-2-7/10=0

We calculate fractions


(-700g^2)/200g^2+150g/200g^2+(-120g)/200g^2-2=0

We multiply all the terms by the denominator


(-700g^2)+150g+(-120g)-2*200g^2=0

Wy multiply elements

(-700g^2)-400g^2+150g+(-120g)=0

We get rid of parentheses

-700g^2-400g^2+150g-120g=0

We add all the numbers together, and all the variables

-1100g^2+30g=0

a = -1100; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-1100)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-1100}=\frac{-60}{-2200}
=3/110
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-1100}=\frac{0}{-2200}
=0
$