3(2m-5)=4m+29

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Solution for 3(2m-5)=4m+29 equation: 



3(2m-5)=4m+29

We move all terms to the left:

3(2m-5)-(4m+29)=0

We multiply parentheses

6m-(4m+29)-15=0

We get rid of parentheses

6m-4m-29-15=0

We add all the numbers together, and all the variables

2m-44=0

We move all terms containing m to the left, all other terms to the right

2m=44

m=44/2

m=22

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