3(2m-2)=2(-3m+9)

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Solution for 3(2m-2)=2(-3m+9) equation: 



3(2m-2)=2(-3m+9)

We move all terms to the left:

3(2m-2)-(2(-3m+9))=0

We multiply parentheses

6m-(2(-3m+9))-6=0



We calculate terms in parentheses: -(2(-3m+9)), so:

2(-3m+9)

We multiply parentheses

-6m+18

Back to the equation:

-(-6m+18)



We get rid of parentheses

6m+6m-18-6=0

We add all the numbers together, and all the variables

12m-24=0

We move all terms containing m to the left, all other terms to the right

12m=24

m=24/12

m=2

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