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1x*3.4x=345125
We move all terms to the left:
1x*3.4x-(345125)=0
Wy multiply elements
3x^2-345125=0
a = 3; b = 0; c = -345125;
Δ = b2-4ac
Δ = 02-4·3·(-345125)
Δ = 4141500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4141500}=\sqrt{100*41415}=\sqrt{100}*\sqrt{41415}=10\sqrt{41415}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{41415}}{2*3}=\frac{0-10\sqrt{41415}}{6} =-\frac{10\sqrt{41415}}{6} =-\frac{5\sqrt{41415}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{41415}}{2*3}=\frac{0+10\sqrt{41415}}{6} =\frac{10\sqrt{41415}}{6} =\frac{5\sqrt{41415}}{3} $
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