3(2i-4)+2=6-4(2i-3)

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Solution for 3(2i-4)+2=6-4(2i-3) equation: 



3(2i-4)+2=6-4(2i-3)

We move all terms to the left:

3(2i-4)+2-(6-4(2i-3))=0

We multiply parentheses

6i-(6-4(2i-3))-12+2=0



We calculate terms in parentheses: -(6-4(2i-3)), so:

6-4(2i-3)

determiningTheFunctionDomain
-4(2i-3)+6

We multiply parentheses

-8i+12+6

We add all the numbers together, and all the variables

-8i+18

Back to the equation:

-(-8i+18)



We add all the numbers together, and all the variables

6i-(-8i+18)-10=0

We get rid of parentheses

6i+8i-18-10=0

We add all the numbers together, and all the variables

14i-28=0

We move all terms containing i to the left, all other terms to the right

14i=28

i=28/14

i=2

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