5(d+3)+2=2(d-3)+5

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Solution for 5(d+3)+2=2(d-3)+5 equation: 



5(d+3)+2=2(d-3)+5

We move all terms to the left:

5(d+3)+2-(2(d-3)+5)=0

We multiply parentheses

5d-(2(d-3)+5)+15+2=0



We calculate terms in parentheses: -(2(d-3)+5), so:

2(d-3)+5

We multiply parentheses

2d-6+5

We add all the numbers together, and all the variables

2d-1

Back to the equation:

-(2d-1)



We add all the numbers together, and all the variables

5d-(2d-1)+17=0

We get rid of parentheses

5d-2d+1+17=0

We add all the numbers together, and all the variables

3d+18=0

We move all terms containing d to the left, all other terms to the right

3d=-18

d=-18/3

d=-6

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