3(2c-8)=2(4-c)

Solution for 3(2c-8)=2(4-c) equation:

3(2c-8)=2(4-c)

We move all terms to the left:

3(2c-8)-(2(4-c))=0

We add all the numbers together, and all the variables

3(2c-8)-(2(-1c+4))=0

We multiply parentheses

6c-(2(-1c+4))-24=0


We calculate terms in parentheses: -(2(-1c+4)), so:

2(-1c+4)

We multiply parentheses

-2c+8

Back to the equation:

-(-2c+8)


We get rid of parentheses

6c+2c-8-24=0

We add all the numbers together, and all the variables

8c-32=0

We move all terms containing c to the left, all other terms to the right

8c=32

c=32/8

c=4